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554085113 is a prime number
BaseRepresentation
bin100001000001101…
…010101011111001
31102121121102212212
4201001222223321
52113321210423
6130551544505
716505434331
oct4101525371
91377542785
10554085113
1126484838a
1213568b135
138aa40a1a
14538340c1
153399d578
hex2106aaf9

554085113 has 2 divisors, whose sum is σ = 554085114. Its totient is φ = 554085112.

The previous prime is 554085083. The next prime is 554085137. The reversal of 554085113 is 311580455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 553802089 + 283024 = 23533^2 + 532^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554085113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 554085113.

It is not a weakly prime, because it can be changed into another prime (554085613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277042556 + 277042557.

It is an arithmetic number, because the mean of its divisors is an integer number (277042557).

Almost surely, 2554085113 is an apocalyptic number.

It is an amenable number.

554085113 is a deficient number, since it is larger than the sum of its proper divisors (1).

554085113 is an equidigital number, since it uses as much as digits as its factorization.

554085113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

The square root of 554085113 is about 23539.0125748724. The cubic root of 554085113 is about 821.3447659702.

The spelling of 554085113 in words is "five hundred fifty-four million, eighty-five thousand, one hundred thirteen".