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554124435041 is a prime number
BaseRepresentation
bin10000001000001000110…
…00111101111001100001
31221222021212212220002202
420010010120331321201
533034321323410131
61102321121422545
755014501661142
oct10040430757141
91858255786082
10554124435041
111a4003885651
128b48719aa55
134033b5299b8
141cb69619ac9
15e63262cbcb
hex810463de61

554124435041 has 2 divisors, whose sum is σ = 554124435042. Its totient is φ = 554124435040.

The previous prime is 554124435037. The next prime is 554124435061. The reversal of 554124435041 is 140534421455.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 410725892641 + 143398542400 = 640879^2 + 378680^2 .

It is a cyclic number.

It is not a de Polignac number, because 554124435041 - 22 = 554124435037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 554124434986 and 554124435004.

It is not a weakly prime, because it can be changed into another prime (554124435001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277062217520 + 277062217521.

It is an arithmetic number, because the mean of its divisors is an integer number (277062217521).

Almost surely, 2554124435041 is an apocalyptic number.

It is an amenable number.

554124435041 is a deficient number, since it is larger than the sum of its proper divisors (1).

554124435041 is an equidigital number, since it uses as much as digits as its factorization.

554124435041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192000, while the sum is 38.

Adding to 554124435041 its reverse (140534421455), we get a palindrome (694658856496).

The spelling of 554124435041 in words is "five hundred fifty-four billion, one hundred twenty-four million, four hundred thirty-five thousand, forty-one".