Base | Representation |
---|---|
bin | 10000001000001000110… |
… | …00111101111001100001 |
3 | 1221222021212212220002202 |
4 | 20010010120331321201 |
5 | 33034321323410131 |
6 | 1102321121422545 |
7 | 55014501661142 |
oct | 10040430757141 |
9 | 1858255786082 |
10 | 554124435041 |
11 | 1a4003885651 |
12 | 8b48719aa55 |
13 | 4033b5299b8 |
14 | 1cb69619ac9 |
15 | e63262cbcb |
hex | 810463de61 |
554124435041 has 2 divisors, whose sum is σ = 554124435042. Its totient is φ = 554124435040.
The previous prime is 554124435037. The next prime is 554124435061. The reversal of 554124435041 is 140534421455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 410725892641 + 143398542400 = 640879^2 + 378680^2 .
It is a cyclic number.
It is not a de Polignac number, because 554124435041 - 22 = 554124435037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 554124434986 and 554124435004.
It is not a weakly prime, because it can be changed into another prime (554124435001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277062217520 + 277062217521.
It is an arithmetic number, because the mean of its divisors is an integer number (277062217521).
Almost surely, 2554124435041 is an apocalyptic number.
It is an amenable number.
554124435041 is a deficient number, since it is larger than the sum of its proper divisors (1).
554124435041 is an equidigital number, since it uses as much as digits as its factorization.
554124435041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 554124435041 its reverse (140534421455), we get a palindrome (694658856496).
The spelling of 554124435041 in words is "five hundred fifty-four billion, one hundred twenty-four million, four hundred thirty-five thousand, forty-one".
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