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554138047 is a prime number
BaseRepresentation
bin100001000001110…
…111100110111111
31102121201010111101
4201001313212333
52113324404142
6130553033531
716506044551
oct4101674677
91377633441
10554138047
11264884131
121356b58a7
138aa5bb48
14538494d1
15339ae0b7
hex210779bf

554138047 has 2 divisors, whose sum is σ = 554138048. Its totient is φ = 554138046.

The previous prime is 554138041. The next prime is 554138063. The reversal of 554138047 is 740831455.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 554138047 - 211 = 554135999 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 554137997 and 554138015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554138041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277069023 + 277069024.

It is an arithmetic number, because the mean of its divisors is an integer number (277069024).

Almost surely, 2554138047 is an apocalyptic number.

554138047 is a deficient number, since it is larger than the sum of its proper divisors (1).

554138047 is an equidigital number, since it uses as much as digits as its factorization.

554138047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 37.

The square root of 554138047 is about 23540.1369367300. The cubic root of 554138047 is about 821.3709206039.

It can be divided in two parts, 554 and 138047, that added together give a triangular number (138601 = T526).

The spelling of 554138047 in words is "five hundred fifty-four million, one hundred thirty-eight thousand, forty-seven".