Base | Representation |
---|---|
bin | 11001001100111011001111… |
… | …10100111101110110001011 |
3 | 21021020001221112012100201222 |
4 | 30212131213310331312023 |
5 | 24230444023432131342 |
6 | 313511243323432255 |
7 | 14446640644442402 |
oct | 1446354764756613 |
9 | 237201845170658 |
10 | 55419704958347 |
11 | 16727401729894 |
12 | 627086308568b |
13 | 24c009564a232 |
14 | d98484196639 |
15 | 6618d8b65ed2 |
hex | 326767d3dd8b |
55419704958347 has 2 divisors, whose sum is σ = 55419704958348. Its totient is φ = 55419704958346.
The previous prime is 55419704958329. The next prime is 55419704958349. The reversal of 55419704958347 is 74385940791455.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55419704958347 - 26 = 55419704958283 is a prime.
Together with 55419704958349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (55419704958349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27709852479173 + 27709852479174.
It is an arithmetic number, because the mean of its divisors is an integer number (27709852479174).
Almost surely, 255419704958347 is an apocalyptic number.
55419704958347 is a deficient number, since it is larger than the sum of its proper divisors (1).
55419704958347 is an equidigital number, since it uses as much as digits as its factorization.
55419704958347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 762048000, while the sum is 71.
The spelling of 55419704958347 in words is "fifty-five trillion, four hundred nineteen billion, seven hundred four million, nine hundred fifty-eight thousand, three hundred forty-seven".
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