Base | Representation |
---|---|
bin | 1010010100101011… |
… | …00011000101001001 |
3 | 112022020111101002211 |
4 | 11022111203011021 |
5 | 42322241124433 |
6 | 2313535025121 |
7 | 254224220251 |
oct | 51225430511 |
9 | 15266441084 |
10 | 5542129993 |
11 | 239442a324 |
12 | 10a806b1a1 |
13 | 6a4274b7a |
14 | 3a80a2961 |
15 | 2268428cd |
hex | 14a563149 |
5542129993 has 2 divisors, whose sum is σ = 5542129994. Its totient is φ = 5542129992.
The previous prime is 5542129991. The next prime is 5542130003. The reversal of 5542129993 is 3999212455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5527476409 + 14653584 = 74347^2 + 3828^2 .
It is a cyclic number.
It is not a de Polignac number, because 5542129993 - 21 = 5542129991 is a prime.
Together with 5542129991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5542129991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2771064996 + 2771064997.
It is an arithmetic number, because the mean of its divisors is an integer number (2771064997).
Almost surely, 25542129993 is an apocalyptic number.
It is an amenable number.
5542129993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5542129993 is an equidigital number, since it uses as much as digits as its factorization.
5542129993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 874800, while the sum is 49.
The square root of 5542129993 is about 74445.4833619878. The cubic root of 5542129993 is about 1769.6697856114.
The spelling of 5542129993 in words is "five billion, five hundred forty-two million, one hundred twenty-nine thousand, nine hundred ninety-three".
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