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55421445520213 is a prime number
BaseRepresentation
bin11001001100111110011111…
…00100101011101101010101
321021020020102211101001202021
430212133033210223231111
524231011110023121323
6313512132142013141
714450032041122653
oct1446371744535525
9237206384331667
1055421445520213
1116728115186773
126271069b771b1
1324c02b2128cb6
14d985ab3d9dd3
1566198b87d05d
hex3267cf92bb55

55421445520213 has 2 divisors, whose sum is σ = 55421445520214. Its totient is φ = 55421445520212.

The previous prime is 55421445520159. The next prime is 55421445520223. The reversal of 55421445520213 is 31202554412455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47987305180369 + 7434140339844 = 6927287^2 + 2726562^2 .

It is a cyclic number.

It is not a de Polignac number, because 55421445520213 - 29 = 55421445519701 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55421445520213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55421445520223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27710722760106 + 27710722760107.

It is an arithmetic number, because the mean of its divisors is an integer number (27710722760107).

Almost surely, 255421445520213 is an apocalyptic number.

It is an amenable number.

55421445520213 is a deficient number, since it is larger than the sum of its proper divisors (1).

55421445520213 is an equidigital number, since it uses as much as digits as its factorization.

55421445520213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960000, while the sum is 43.

Adding to 55421445520213 its reverse (31202554412455), we get a palindrome (86623999932668).

The spelling of 55421445520213 in words is "fifty-five trillion, four hundred twenty-one billion, four hundred forty-five million, five hundred twenty thousand, two hundred thirteen".