Base | Representation |
---|---|
bin | 111111000001001010010101… |
… | …1111100010100011001011110 |
3 | 2200200122212001200110222011102 |
4 | 1332002110223330110121132 |
5 | 1040123333032410442114 |
6 | 5242532040042553102 |
7 | 224520554361616154 |
oct | 17602245374243136 |
9 | 2620585050428142 |
10 | 554313511421534 |
11 | 1506920493017a7 |
12 | 52205809508792 |
13 | 1aa3b703036677 |
14 | 9ac4cba75b3d4 |
15 | 4413e76e9b2de |
hex | 1f8252bf1465e |
554313511421534 has 4 divisors (see below), whose sum is σ = 831470267132304. Its totient is φ = 277156755710766.
The previous prime is 554313511421533. The next prime is 554313511421567. The reversal of 554313511421534 is 435124115313455.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×5543135114215342 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (554313511421533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 138578377855382 + ... + 138578377855385.
It is an arithmetic number, because the mean of its divisors is an integer number (207867566783076).
Almost surely, 2554313511421534 is an apocalyptic number.
554313511421534 is a deficient number, since it is larger than the sum of its proper divisors (277156755710770).
554313511421534 is a wasteful number, since it uses less digits than its factorization.
554313511421534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277156755710769.
The product of its digits is 2160000, while the sum is 47.
Adding to 554313511421534 its reverse (435124115313455), we get a palindrome (989437626734989).
The spelling of 554313511421534 in words is "five hundred fifty-four trillion, three hundred thirteen billion, five hundred eleven million, four hundred twenty-one thousand, five hundred thirty-four".
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