Base | Representation |
---|---|
bin | 110011101000001111… |
… | …010010101111101011 |
3 | 12022002102111001112221 |
4 | 303220033102233223 |
5 | 1402013044234403 |
6 | 41244504214511 |
7 | 4001516430634 |
oct | 635017225753 |
9 | 168072431487 |
10 | 55435930603 |
11 | 21568157189 |
12 | a8b146a437 |
13 | 52c6010401 |
14 | 297c66a88b |
15 | 1696c0adbd |
hex | ce83d2beb |
55435930603 has 2 divisors, whose sum is σ = 55435930604. Its totient is φ = 55435930602.
The previous prime is 55435930601. The next prime is 55435930609. The reversal of 55435930603 is 30603953455.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55435930603 - 21 = 55435930601 is a prime.
Together with 55435930601, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 55435930603.
It is not a weakly prime, because it can be changed into another prime (55435930601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27717965301 + 27717965302.
It is an arithmetic number, because the mean of its divisors is an integer number (27717965302).
Almost surely, 255435930603 is an apocalyptic number.
55435930603 is a deficient number, since it is larger than the sum of its proper divisors (1).
55435930603 is an equidigital number, since it uses as much as digits as its factorization.
55435930603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729000, while the sum is 43.
The spelling of 55435930603 in words is "fifty-five billion, four hundred thirty-five million, nine hundred thirty thousand, six hundred three".
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