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554440130437 is a prime number
BaseRepresentation
bin10000001000101110011…
…01001111111110000101
31222000002212220212202211
420010113031033332011
533040443133133222
61102412320103421
755025354230654
oct10042715177605
91860085825684
10554440130437
111a4155aaa236
128b554a64b71
134038ba617cb
141cb9951719b
15e6501dc277
hex811734ff85

554440130437 has 2 divisors, whose sum is σ = 554440130438. Its totient is φ = 554440130436.

The previous prime is 554440130429. The next prime is 554440130441. The reversal of 554440130437 is 734031044455.

554440130437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 281323099201 + 273117031236 = 530399^2 + 522606^2 .

It is a cyclic number.

It is not a de Polignac number, because 554440130437 - 23 = 554440130429 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 554440130437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554440130137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277220065218 + 277220065219.

It is an arithmetic number, because the mean of its divisors is an integer number (277220065219).

Almost surely, 2554440130437 is an apocalyptic number.

It is an amenable number.

554440130437 is a deficient number, since it is larger than the sum of its proper divisors (1).

554440130437 is an equidigital number, since it uses as much as digits as its factorization.

554440130437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 40.

The spelling of 554440130437 in words is "five hundred fifty-four billion, four hundred forty million, one hundred thirty thousand, four hundred thirty-seven".