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554497131197 is a prime number
BaseRepresentation
bin10000001000110101001…
…10101100001010111101
31222000020212011211010002
420010122212230022331
533041102231144242
61102422113524045
755026645563642
oct10043246541275
91860225154102
10554497131197
111a41851a17a9
128b56bb73625
134039a7cb579
141cba2d13dc9
15e6551eb432
hex811a9ac2bd

554497131197 has 2 divisors, whose sum is σ = 554497131198. Its totient is φ = 554497131196.

The previous prime is 554497131157. The next prime is 554497131211. The reversal of 554497131197 is 791131794455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 543915100036 + 10582031161 = 737506^2 + 102869^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554497131197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554497131107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277248565598 + 277248565599.

It is an arithmetic number, because the mean of its divisors is an integer number (277248565599).

Almost surely, 2554497131197 is an apocalyptic number.

It is an amenable number.

554497131197 is a deficient number, since it is larger than the sum of its proper divisors (1).

554497131197 is an equidigital number, since it uses as much as digits as its factorization.

554497131197 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4762800, while the sum is 56.

The spelling of 554497131197 in words is "five hundred fifty-four billion, four hundred ninety-seven million, one hundred thirty-one thousand, one hundred ninety-seven".