55451220043 has 2 divisors, whose sum is σ = 55451220044. Its totient is φ = 55451220042.

The previous prime is 55451220037. The next prime is 55451220049. The reversal of 55451220043 is 34002215455.

55451220043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (55451220037) and next prime (55451220049).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-55451220043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55451219987 and 55451220014.

It is not a weakly prime, because it can be changed into another prime (55451220049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27725610021 + 27725610022.

It is an arithmetic number, because the mean of its divisors is an integer number (27725610022).

Almost surely, 2^55451220043 is an apocalyptic number.

55451220043 is a deficient number, since it is larger than the sum of its proper divisors (1).

55451220043 is an equidigital number, since it uses as much as digits as its factorization.

55451220043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 31.

Adding to 55451220043 its reverse (34002215455), we get a palindrome (89453435498).

The spelling of 55451220043 in words is "fifty-five billion, four hundred fifty-one million, two hundred twenty thousand, forty-three".