Base | Representation |
---|---|
bin | 110011101010010010… |
… | …110011011111011001 |
3 | 12022011211100120100102 |
4 | 303222102303133121 |
5 | 1402100410434333 |
6 | 41252135145145 |
7 | 4002415445051 |
oct | 635222633731 |
9 | 168154316312 |
10 | 55470405593 |
11 | 21585663809 |
12 | a900b151b5 |
13 | 53001c1205 |
14 | 2983082561 |
15 | 1699c6aae8 |
hex | cea4b37d9 |
55470405593 has 2 divisors, whose sum is σ = 55470405594. Its totient is φ = 55470405592.
The previous prime is 55470405509. The next prime is 55470405623. The reversal of 55470405593 is 39550407455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35438815504 + 20031590089 = 188252^2 + 141533^2 .
It is a cyclic number.
It is not a de Polignac number, because 55470405593 - 222 = 55466211289 is a prime.
It is a super-3 number, since 3×554704055933 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (55470402593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27735202796 + 27735202797.
It is an arithmetic number, because the mean of its divisors is an integer number (27735202797).
Almost surely, 255470405593 is an apocalyptic number.
It is an amenable number.
55470405593 is a deficient number, since it is larger than the sum of its proper divisors (1).
55470405593 is an equidigital number, since it uses as much as digits as its factorization.
55470405593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1890000, while the sum is 47.
The spelling of 55470405593 in words is "fifty-five billion, four hundred seventy million, four hundred five thousand, five hundred ninety-three".
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