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55470405593 is a prime number
BaseRepresentation
bin110011101010010010…
…110011011111011001
312022011211100120100102
4303222102303133121
51402100410434333
641252135145145
74002415445051
oct635222633731
9168154316312
1055470405593
1121585663809
12a900b151b5
1353001c1205
142983082561
151699c6aae8
hexcea4b37d9

55470405593 has 2 divisors, whose sum is σ = 55470405594. Its totient is φ = 55470405592.

The previous prime is 55470405509. The next prime is 55470405623. The reversal of 55470405593 is 39550407455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35438815504 + 20031590089 = 188252^2 + 141533^2 .

It is a cyclic number.

It is not a de Polignac number, because 55470405593 - 222 = 55466211289 is a prime.

It is a super-3 number, since 3×554704055933 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (55470402593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27735202796 + 27735202797.

It is an arithmetic number, because the mean of its divisors is an integer number (27735202797).

Almost surely, 255470405593 is an apocalyptic number.

It is an amenable number.

55470405593 is a deficient number, since it is larger than the sum of its proper divisors (1).

55470405593 is an equidigital number, since it uses as much as digits as its factorization.

55470405593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1890000, while the sum is 47.

The spelling of 55470405593 in words is "fifty-five billion, four hundred seventy million, four hundred five thousand, five hundred ninety-three".