Base | Representation |
---|---|
bin | 11001001110011011001110… |
… | …11000100010111111110101 |
3 | 21021101222221220001012101121 |
4 | 30213031213120202333311 |
5 | 24232320043200202033 |
6 | 313551045020423541 |
7 | 14453443652525644 |
oct | 1447154730427765 |
9 | 237358856035347 |
10 | 55471237115893 |
11 | 16747246246545 |
12 | 627a8450a7bb1 |
13 | 24c4bb895b251 |
14 | d9ab7219b35b |
15 | 662e02ca862d |
hex | 327367622ff5 |
55471237115893 has 2 divisors, whose sum is σ = 55471237115894. Its totient is φ = 55471237115892.
The previous prime is 55471237115809. The next prime is 55471237115939. The reversal of 55471237115893 is 39851173217455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54624767194449 + 846469921444 = 7390857^2 + 920038^2 .
It is a cyclic number.
It is not a de Polignac number, because 55471237115893 - 221 = 55471235018741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55471237110893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27735618557946 + 27735618557947.
It is an arithmetic number, because the mean of its divisors is an integer number (27735618557947).
Almost surely, 255471237115893 is an apocalyptic number.
It is an amenable number.
55471237115893 is a deficient number, since it is larger than the sum of its proper divisors (1).
55471237115893 is an equidigital number, since it uses as much as digits as its factorization.
55471237115893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31752000, while the sum is 61.
The spelling of 55471237115893 in words is "fifty-five trillion, four hundred seventy-one billion, two hundred thirty-seven million, one hundred fifteen thousand, eight hundred ninety-three".
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