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5548093696001 is a prime number
BaseRepresentation
bin101000010111100010000…
…1001110110100000000001
3201122101121012002201210202
41100233010021312200001
51211344443441233001
615444431542334545
71111556635210613
oct120570411664001
921571535081722
105548093696001
111849a2a28665a
1275731142a455
1331324c051a0c
1415275a070db3
15994ba69396b
hex50bc4276801

5548093696001 has 2 divisors, whose sum is σ = 5548093696002. Its totient is φ = 5548093696000.

The previous prime is 5548093695983. The next prime is 5548093696003. The reversal of 5548093696001 is 1006963908455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4821542031601 + 726551664400 = 2195801^2 + 852380^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5548093696001 is a prime.

It is a super-3 number, since 3×55480936960013 (a number of 39 digits) contains 333 as substring.

Together with 5548093696003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5548093696003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2774046848000 + 2774046848001.

It is an arithmetic number, because the mean of its divisors is an integer number (2774046848001).

Almost surely, 25548093696001 is an apocalyptic number.

It is an amenable number.

5548093696001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5548093696001 is an equidigital number, since it uses as much as digits as its factorization.

5548093696001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 56.

The spelling of 5548093696001 in words is "five trillion, five hundred forty-eight billion, ninety-three million, six hundred ninety-six thousand, one".