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55500691153 is a prime number
BaseRepresentation
bin110011101100000110…
…010101011011010001
312022020221100020022211
4303230012111123101
51402131134104103
641255140232121
74003234043125
oct635406253321
9168227306284
1055500691153
11215a07697a6
12a90b09b641
13530656616b
1429870c7585
15169c74e36d
hexcec1956d1

55500691153 has 2 divisors, whose sum is σ = 55500691154. Its totient is φ = 55500691152.

The previous prime is 55500691151. The next prime is 55500691189. The reversal of 55500691153 is 35119600555.

55500691153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28948640449 + 26552050704 = 170143^2 + 162948^2 .

It is a cyclic number.

It is not a de Polignac number, because 55500691153 - 21 = 55500691151 is a prime.

Together with 55500691151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (55500691151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27750345576 + 27750345577.

It is an arithmetic number, because the mean of its divisors is an integer number (27750345577).

Almost surely, 255500691153 is an apocalyptic number.

It is an amenable number.

55500691153 is a deficient number, since it is larger than the sum of its proper divisors (1).

55500691153 is an equidigital number, since it uses as much as digits as its factorization.

55500691153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 101250, while the sum is 40.

The spelling of 55500691153 in words is "fifty-five billion, five hundred million, six hundred ninety-one thousand, one hundred fifty-three".