Base | Representation |
---|---|
bin | 110011101100000111… |
… | …001010101001001101 |
3 | 12022020221202022100011 |
4 | 303230013022221031 |
5 | 1402131213043013 |
6 | 41255145033221 |
7 | 4003235641465 |
oct | 635407125115 |
9 | 168227668304 |
10 | 55500909133 |
11 | 215a08a854a |
12 | a90b185811 |
13 | 5306611447 |
14 | 2987142ba5 |
15 | 169c793c3d |
hex | cec1caa4d |
55500909133 has 2 divisors, whose sum is σ = 55500909134. Its totient is φ = 55500909132.
The previous prime is 55500909077. The next prime is 55500909143. The reversal of 55500909133 is 33190900555.
55500909133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43523138884 + 11977770249 = 208622^2 + 109443^2 .
It is a cyclic number.
It is not a de Polignac number, because 55500909133 - 221 = 55498811981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55500909143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27750454566 + 27750454567.
It is an arithmetic number, because the mean of its divisors is an integer number (27750454567).
Almost surely, 255500909133 is an apocalyptic number.
It is an amenable number.
55500909133 is a deficient number, since it is larger than the sum of its proper divisors (1).
55500909133 is an equidigital number, since it uses as much as digits as its factorization.
55500909133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91125, while the sum is 40.
The spelling of 55500909133 in words is "fifty-five billion, five hundred million, nine hundred nine thousand, one hundred thirty-three".
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