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5550506000129 is a prime number
BaseRepresentation
bin101000011000101001111…
…1100000011111100000001
3201122121211022021110222002
41100301103330003330001
51211414414014001004
615445511154353345
71112003466361346
oct120612374037401
921577738243862
105550506000129
11184aa57a32432
1275788528b855
13313544a57bcc
141529085b47cd
15995ac34a61e
hex50c53f03f01

5550506000129 has 2 divisors, whose sum is σ = 5550506000130. Its totient is φ = 5550506000128.

The previous prime is 5550506000093. The next prime is 5550506000153. The reversal of 5550506000129 is 9210006050555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5545765953025 + 4740047104 = 2354945^2 + 68848^2 .

It is a cyclic number.

It is not a de Polignac number, because 5550506000129 - 28 = 5550505999873 is a prime.

It is a super-4 number, since 4×55505060001294 (a number of 52 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5550506000092 and 5550506000101.

It is not a weakly prime, because it can be changed into another prime (5550506000329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775253000064 + 2775253000065.

It is an arithmetic number, because the mean of its divisors is an integer number (2775253000065).

Almost surely, 25550506000129 is an apocalyptic number.

It is an amenable number.

5550506000129 is a deficient number, since it is larger than the sum of its proper divisors (1).

5550506000129 is an equidigital number, since it uses as much as digits as its factorization.

5550506000129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67500, while the sum is 38.

The spelling of 5550506000129 in words is "five trillion, five hundred fifty billion, five hundred six million, one hundred twenty-nine", and thus it is an aban number.