Base | Representation |
---|---|
bin | 110011101101111000… |
… | …010000011001110001 |
3 | 12022100000112110210222 |
4 | 303231320100121301 |
5 | 1402211310224433 |
6 | 41302124302425 |
7 | 4004045633534 |
oct | 635570203161 |
9 | 168300473728 |
10 | 55530554993 |
11 | 21606606961 |
12 | a9190a1a15 |
13 | 530c7c1184 |
14 | 298b05ca1b |
15 | 16a019cb98 |
hex | cede10671 |
55530554993 has 2 divisors, whose sum is σ = 55530554994. Its totient is φ = 55530554992.
The previous prime is 55530554983. The next prime is 55530555023. The reversal of 55530554993 is 39945503555.
55530554993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52517972224 + 3012582769 = 229168^2 + 54887^2 .
It is a cyclic number.
It is not a de Polignac number, because 55530554993 - 24 = 55530554977 is a prime.
It is not a weakly prime, because it can be changed into another prime (55530554923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27765277496 + 27765277497.
It is an arithmetic number, because the mean of its divisors is an integer number (27765277497).
Almost surely, 255530554993 is an apocalyptic number.
It is an amenable number.
55530554993 is a deficient number, since it is larger than the sum of its proper divisors (1).
55530554993 is an equidigital number, since it uses as much as digits as its factorization.
55530554993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9112500, while the sum is 53.
The spelling of 55530554993 in words is "fifty-five billion, five hundred thirty million, five hundred fifty-four thousand, nine hundred ninety-three".
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