Base | Representation |
---|---|
bin | 10000001010100101110… |
… | …01010010010111100101 |
3 | 1222002200200020021012011 |
4 | 20011102321102113211 |
5 | 33100021012432331 |
6 | 1103055531354221 |
7 | 55062234052135 |
oct | 10052271222745 |
9 | 1862620207164 |
10 | 555441530341 |
11 | 1a461a299865 |
12 | 8b7942b2971 |
13 | 404bb36bc29 |
14 | 1cc5250aac5 |
15 | e6ad0983b1 |
hex | 8152e525e5 |
555441530341 has 2 divisors, whose sum is σ = 555441530342. Its totient is φ = 555441530340.
The previous prime is 555441530333. The next prime is 555441530377. The reversal of 555441530341 is 143035144555.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 499495562500 + 55945967841 = 706750^2 + 236529^2 .
It is a cyclic number.
It is not a de Polignac number, because 555441530341 - 23 = 555441530333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 555441530294 and 555441530303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (555441530741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277720765170 + 277720765171.
It is an arithmetic number, because the mean of its divisors is an integer number (277720765171).
Almost surely, 2555441530341 is an apocalyptic number.
It is an amenable number.
555441530341 is a deficient number, since it is larger than the sum of its proper divisors (1).
555441530341 is an equidigital number, since it uses as much as digits as its factorization.
555441530341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 555441530341 its reverse (143035144555), we get a palindrome (698476674896).
The spelling of 555441530341 in words is "five hundred fifty-five billion, four hundred forty-one million, five hundred thirty thousand, three hundred forty-one".
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