Base | Representation |
---|---|
bin | 11001010000101111110111… |
… | …01001111011110010110000 |
3 | 21021200121221002011200001022 |
4 | 30220113323221323302300 |
5 | 24240122004213110300 |
6 | 314051443123155012 |
7 | 14462300261025653 |
oct | 1450277351736260 |
9 | 237617832150038 |
10 | 55551034113200 |
11 | 167780745a96aa |
12 | 62921b4b15a68 |
13 | 24cc5949c7112 |
14 | da0981db189a |
15 | 665023528285 |
hex | 3285fba7bcb0 |
55551034113200 has 60 divisors (see below), whose sum is σ = 134685775704480. Its totient is φ = 22016556622080.
The previous prime is 55551034113193. The next prime is 55551034113257. The reversal of 55551034113200 is 231143015555.
It is a super-2 number, since 2×555510341132002 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 637009544 + ... + 637096743.
It is an arithmetic number, because the mean of its divisors is an integer number (2244762928408).
Almost surely, 255551034113200 is an apocalyptic number.
55551034113200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55551034113200 is an abundant number, since it is smaller than the sum of its proper divisors (79134741591280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55551034113200 is a wasteful number, since it uses less digits than its factorization.
55551034113200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1274106414 (or 1274106403 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 35.
Adding to 55551034113200 its reverse (231143015555), we get a palindrome (55782177128755).
The spelling of 55551034113200 in words is "fifty-five trillion, five hundred fifty-one billion, thirty-four million, one hundred thirteen thousand, two hundred".
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