Base | Representation |
---|---|
bin | 10000001010110000011… |
… | …11101111000111110001 |
3 | 1222002220221011002212202 |
4 | 20011120033233013301 |
5 | 33100212003120421 |
6 | 1103112455432545 |
7 | 55064404102211 |
oct | 10053017570761 |
9 | 1862827132782 |
10 | 555531301361 |
11 | 1a4665a34093 |
12 | 8b7ba385755 |
13 | 40503b4088a |
14 | 1cc603d8241 |
15 | e6b5dcc10b |
hex | 81583ef1f1 |
555531301361 has 2 divisors, whose sum is σ = 555531301362. Its totient is φ = 555531301360.
The previous prime is 555531301357. The next prime is 555531301439. The reversal of 555531301361 is 163103135555.
555531301361 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 492502186225 + 63029115136 = 701785^2 + 251056^2 .
It is a cyclic number.
It is not a de Polignac number, because 555531301361 - 22 = 555531301357 is a prime.
It is not a weakly prime, because it can be changed into another prime (555531301321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277765650680 + 277765650681.
It is an arithmetic number, because the mean of its divisors is an integer number (277765650681).
Almost surely, 2555531301361 is an apocalyptic number.
It is an amenable number.
555531301361 is a deficient number, since it is larger than the sum of its proper divisors (1).
555531301361 is an equidigital number, since it uses as much as digits as its factorization.
555531301361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 101250, while the sum is 38.
The spelling of 555531301361 in words is "five hundred fifty-five billion, five hundred thirty-one million, three hundred one thousand, three hundred sixty-one".
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