Search a number
-
+
555555412303 is a prime number
BaseRepresentation
bin10000001010110011010…
…11101101100101001111
31222002222121112001212121
420011121223231211033
533100234141143203
61103115120313411
755065116042413
oct10053153554517
91862877461777
10555555412303
111a4678601a91
128b806472867
1340508b331c8
141cc636b2d43
15e6b80910bd
hex8159aed94f

555555412303 has 2 divisors, whose sum is σ = 555555412304. Its totient is φ = 555555412302.

The previous prime is 555555412297. The next prime is 555555412351. The reversal of 555555412303 is 303214555555.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 555555412303 - 229 = 555018541391 is a prime.

It is a super-2 number, since 2×5555554123032 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 555555412303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (555555412403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277777706151 + 277777706152.

It is an arithmetic number, because the mean of its divisors is an integer number (277777706152).

Almost surely, 2555555412303 is an apocalyptic number.

555555412303 is a deficient number, since it is larger than the sum of its proper divisors (1).

555555412303 is an equidigital number, since it uses as much as digits as its factorization.

555555412303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1125000, while the sum is 43.

Adding to 555555412303 its reverse (303214555555), we get a palindrome (858769967858).

The spelling of 555555412303 in words is "five hundred fifty-five billion, five hundred fifty-five million, four hundred twelve thousand, three hundred three".