Base | Representation |
---|---|
bin | 101000011101010101010… |
… | …1011000101001010111001 |
3 | 201200120202100220111000021 |
4 | 1100322222223011022321 |
5 | 1212101002040213423 |
6 | 15454252032010441 |
7 | 1112510432335141 |
oct | 120725253051271 |
9 | 21616670814007 |
10 | 5560551101113 |
11 | 1854242151488 |
12 | 759809390a21 |
13 | 314485ba6948 |
14 | 1531bc717921 |
15 | 9999916695d |
hex | 50eaaac52b9 |
5560551101113 has 2 divisors, whose sum is σ = 5560551101114. Its totient is φ = 5560551101112.
The previous prime is 5560551101099. The next prime is 5560551101123. The reversal of 5560551101113 is 3111011550655.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5487081372304 + 73469728809 = 2342452^2 + 271053^2 .
It is a cyclic number.
It is not a de Polignac number, because 5560551101113 - 229 = 5560014230201 is a prime.
It is not a weakly prime, because it can be changed into another prime (5560551101123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780275550556 + 2780275550557.
It is an arithmetic number, because the mean of its divisors is an integer number (2780275550557).
Almost surely, 25560551101113 is an apocalyptic number.
It is an amenable number.
5560551101113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5560551101113 is an equidigital number, since it uses as much as digits as its factorization.
5560551101113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11250, while the sum is 34.
Adding to 5560551101113 its reverse (3111011550655), we get a palindrome (8671562651768).
The spelling of 5560551101113 in words is "five trillion, five hundred sixty billion, five hundred fifty-one million, one hundred one thousand, one hundred thirteen".
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