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5561172528061 is a prime number
BaseRepresentation
bin101000011101100111110…
…1101101000101110111101
3201200122100200020020112011
41100323033231220232331
51212103240131344221
615454433431211221
71112532016355413
oct120731755505675
921618320206464
105561172528061
111854530a04777
12759961516b11
133145548652b7
1415323b07b2b3
15999d39b81e1
hex50ecfb68bbd

5561172528061 has 2 divisors, whose sum is σ = 5561172528062. Its totient is φ = 5561172528060.

The previous prime is 5561172528019. The next prime is 5561172528083. The reversal of 5561172528061 is 1608252711655.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5518975562500 + 42196965561 = 2349250^2 + 205419^2 .

It is a cyclic number.

It is not a de Polignac number, because 5561172528061 - 225 = 5561138973629 is a prime.

It is a super-3 number, since 3×55611725280613 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5561172527996 and 5561172528014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5561172528011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780586264030 + 2780586264031.

It is an arithmetic number, because the mean of its divisors is an integer number (2780586264031).

Almost surely, 25561172528061 is an apocalyptic number.

It is an amenable number.

5561172528061 is a deficient number, since it is larger than the sum of its proper divisors (1).

5561172528061 is an equidigital number, since it uses as much as digits as its factorization.

5561172528061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008000, while the sum is 49.

The spelling of 5561172528061 in words is "five trillion, five hundred sixty-one billion, one hundred seventy-two million, five hundred twenty-eight thousand, sixty-one".