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55641331406533 is a prime number
BaseRepresentation
bin11001010011011000000011…
…10010110001011011000101
321022000021000001110102221211
430221230001302301123011
524243111421320002113
6314201135203411421
714501645030246635
oct1451540162613305
9238007001412854
1055641331406533
11168023a1015664
1262a77b5383b71
132507c552aa1c2
14da50aa57a6c5
1566755aa2bb3d
hex329b01cb16c5

55641331406533 has 2 divisors, whose sum is σ = 55641331406534. Its totient is φ = 55641331406532.

The previous prime is 55641331406519. The next prime is 55641331406537. The reversal of 55641331406533 is 33560413314655.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53225224895844 + 2416106510689 = 7295562^2 + 1554383^2 .

It is a cyclic number.

It is not a de Polignac number, because 55641331406533 - 29 = 55641331406021 is a prime.

It is a super-2 number, since 2×556413314065332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55641331406537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27820665703266 + 27820665703267.

It is an arithmetic number, because the mean of its divisors is an integer number (27820665703267).

Almost surely, 255641331406533 is an apocalyptic number.

It is an amenable number.

55641331406533 is a deficient number, since it is larger than the sum of its proper divisors (1).

55641331406533 is an equidigital number, since it uses as much as digits as its factorization.

55641331406533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832000, while the sum is 49.

The spelling of 55641331406533 in words is "fifty-five trillion, six hundred forty-one billion, three hundred thirty-one million, four hundred six thousand, five hundred thirty-three".