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556440313443142 = 21312123817990241
BaseRepresentation
bin111111010000101000101101…
…1001110001011001101000110
32200222012011201011200221010011
41332201101123032023031012
51040413204230220140032
65251241052343220434
7225130325456541352
oct17641213316131506
92628164634627104
10556440313443142
1115133201462a167
12524a9a3b14771a
131ab64133a60c4b
149b59bd7a96462
15444e45218d247
hex1fa145b38b346

556440313443142 has 8 divisors (see below), whose sum is σ = 841031924135832. Its totient is φ = 276096338731200.

The previous prime is 556440313443089. The next prime is 556440313443143. The reversal of 556440313443142 is 241344313044655.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (556440313443143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1061908994859 + ... + 1061908995382.

It is an arithmetic number, because the mean of its divisors is an integer number (105128990516979).

Almost surely, 2556440313443142 is an apocalyptic number.

556440313443142 is a deficient number, since it is larger than the sum of its proper divisors (284591610692690).

556440313443142 is a wasteful number, since it uses less digits than its factorization.

556440313443142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2123817990374.

The product of its (nonzero) digits is 8294400, while the sum is 49.

Adding to 556440313443142 its reverse (241344313044655), we get a palindrome (797784626487797).

The spelling of 556440313443142 in words is "five hundred fifty-six trillion, four hundred forty billion, three hundred thirteen million, four hundred forty-three thousand, one hundred forty-two".

Divisors: 1 2 131 262 2123817990241 4247635980482 278220156721571 556440313443142