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55644443201231 is a prime number
BaseRepresentation
bin11001010011011101110110…
…10001010100111011001111
321022000120000220211222210022
430221232323101110323033
524243134304424414411
6314202412044132355
714502115114130453
oct1451567321247317
9238016026758708
1055644443201231
11168037485a3015
1262a83235370bb
13250832cba4941
14da52c3964663
1566768dd04edb
hex329bbb454ecf

55644443201231 has 2 divisors, whose sum is σ = 55644443201232. Its totient is φ = 55644443201230.

The previous prime is 55644443201209. The next prime is 55644443201287. The reversal of 55644443201231 is 13210234444655.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55644443201231 - 210 = 55644443200207 is a prime.

It is a super-2 number, since 2×556444432012312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55644043201231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27822221600615 + 27822221600616.

It is an arithmetic number, because the mean of its divisors is an integer number (27822221600616).

Almost surely, 255644443201231 is an apocalyptic number.

55644443201231 is a deficient number, since it is larger than the sum of its proper divisors (1).

55644443201231 is an equidigital number, since it uses as much as digits as its factorization.

55644443201231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1382400, while the sum is 44.

Adding to 55644443201231 its reverse (13210234444655), we get a palindrome (68854677645886).

The spelling of 55644443201231 in words is "fifty-five trillion, six hundred forty-four billion, four hundred forty-three million, two hundred one thousand, two hundred thirty-one".