Base | Representation |
---|---|
bin | 11001010100010101100110… |
… | …10000111100001010001101 |
3 | 21022010102021211021111002221 |
4 | 30222022303100330022031 |
5 | 24244132104123400013 |
6 | 314224242033415341 |
7 | 14504224610564254 |
oct | 1452126320741215 |
9 | 238112254244087 |
10 | 55674373653133 |
11 | 16815407554584 |
12 | 62b209710a551 |
13 | 250b0bca28b01 |
14 | da6922a6779b |
15 | 66834179208d |
hex | 32a2b343c28d |
55674373653133 has 2 divisors, whose sum is σ = 55674373653134. Its totient is φ = 55674373653132.
The previous prime is 55674373653127. The next prime is 55674373653181. The reversal of 55674373653133 is 33135637347655.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31061483398089 + 24612890255044 = 5573283^2 + 4961138^2 .
It is a cyclic number.
It is not a de Polignac number, because 55674373653133 - 29 = 55674373652621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55674373653113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27837186826566 + 27837186826567.
It is an arithmetic number, because the mean of its divisors is an integer number (27837186826567).
Almost surely, 255674373653133 is an apocalyptic number.
It is an amenable number.
55674373653133 is a deficient number, since it is larger than the sum of its proper divisors (1).
55674373653133 is an equidigital number, since it uses as much as digits as its factorization.
55674373653133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 214326000, while the sum is 61.
The spelling of 55674373653133 in words is "fifty-five trillion, six hundred seventy-four billion, three hundred seventy-three million, six hundred fifty-three thousand, one hundred thirty-three".
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