Base | Representation |
---|---|
bin | 11001010101000110011101… |
… | …10011110110100101010111 |
3 | 21022012220222222022011000021 |
4 | 30222203032303312211113 |
5 | 24300044320013001233 |
6 | 314244301023130011 |
7 | 14506143634444642 |
oct | 1452431663664527 |
9 | 238186888264007 |
10 | 55700605593943 |
11 | 16825548822a02 |
12 | 62b7198143907 |
13 | 251071055ac8b |
14 | da7cd0896a59 |
15 | 668d796ade2d |
hex | 32a8cecf6957 |
55700605593943 has 2 divisors, whose sum is σ = 55700605593944. Its totient is φ = 55700605593942.
The previous prime is 55700605593937. The next prime is 55700605593959. The reversal of 55700605593943 is 34939550600755.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55700605593943 - 25 = 55700605593911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55700605593923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27850302796971 + 27850302796972.
It is an arithmetic number, because the mean of its divisors is an integer number (27850302796972).
Almost surely, 255700605593943 is an apocalyptic number.
55700605593943 is a deficient number, since it is larger than the sum of its proper divisors (1).
55700605593943 is an equidigital number, since it uses as much as digits as its factorization.
55700605593943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76545000, while the sum is 61.
The spelling of 55700605593943 in words is "fifty-five trillion, seven hundred billion, six hundred five million, five hundred ninety-three thousand, nine hundred forty-three".
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