Search a number
-
+
55711194101341 is a prime number
BaseRepresentation
bin11001010101011010001011…
…11011110011011001011101
321022020221022220110001111221
430222231011323303121131
524300233011142220331
6314253211431413341
714510000216331622
oct1452550573633135
9238227286401457
1055711194101341
1116829a91756269
1262b9252224251
13251170a14bc7c
14da8616c50349
15669299069711
hex32ab45ef365d

55711194101341 has 2 divisors, whose sum is σ = 55711194101342. Its totient is φ = 55711194101340.

The previous prime is 55711194101327. The next prime is 55711194101417. The reversal of 55711194101341 is 14310149111755.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55338051492025 + 373142609316 = 7438955^2 + 610854^2 .

It is a cyclic number.

It is not a de Polignac number, because 55711194101341 - 29 = 55711194100829 is a prime.

It is a super-3 number, since 3×557111941013413 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55711194141341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27855597050670 + 27855597050671.

It is an arithmetic number, because the mean of its divisors is an integer number (27855597050671).

Almost surely, 255711194101341 is an apocalyptic number.

It is an amenable number.

55711194101341 is a deficient number, since it is larger than the sum of its proper divisors (1).

55711194101341 is an equidigital number, since it uses as much as digits as its factorization.

55711194101341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 43.

The spelling of 55711194101341 in words is "fifty-five trillion, seven hundred eleven billion, one hundred ninety-four million, one hundred one thousand, three hundred forty-one".