Search a number
-
+
5574902121497 is a prime number
BaseRepresentation
bin101000100100000001000…
…0011111000010000011001
3201201221210111212212000202
41101020002003320100121
51212314344420341442
615505024044111545
71113526162110542
oct121100203702031
921657714785022
105574902121497
11185a336a01505
127605535355b5
13315932138297
14153b806854c9
159a038ed5c32
hex512020f8419

5574902121497 has 2 divisors, whose sum is σ = 5574902121498. Its totient is φ = 5574902121496.

The previous prime is 5574902121479. The next prime is 5574902121499. The reversal of 5574902121497 is 7941212094755.

Together with previous prime (5574902121479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3456535398976 + 2118366722521 = 1859176^2 + 1455461^2 .

It is a cyclic number.

It is not a de Polignac number, because 5574902121497 - 28 = 5574902121241 is a prime.

Together with 5574902121499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5574902121499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2787451060748 + 2787451060749.

It is an arithmetic number, because the mean of its divisors is an integer number (2787451060749).

Almost surely, 25574902121497 is an apocalyptic number.

It is an amenable number.

5574902121497 is a deficient number, since it is larger than the sum of its proper divisors (1).

5574902121497 is an equidigital number, since it uses as much as digits as its factorization.

5574902121497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6350400, while the sum is 56.

The spelling of 5574902121497 in words is "five trillion, five hundred seventy-four billion, nine hundred two million, one hundred twenty-one thousand, four hundred ninety-seven".