Base | Representation |
---|---|
bin | 1010011010110110… |
… | …10011010111011101 |
3 | 112102212001010102022 |
4 | 11031123103113131 |
5 | 42424024021031 |
6 | 2323030105525 |
7 | 255423650564 |
oct | 51533232735 |
9 | 15385033368 |
10 | 5593970141 |
11 | 2410717621 |
12 | 11014ab2a5 |
13 | 6b1c25a06 |
14 | 3b0d18bdb |
15 | 22b18297b |
hex | 14d6d35dd |
5593970141 has 2 divisors, whose sum is σ = 5593970142. Its totient is φ = 5593970140.
The previous prime is 5593970111. The next prime is 5593970159. The reversal of 5593970141 is 1410793955.
5593970141 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5129567641 + 464402500 = 71621^2 + 21550^2 .
It is a cyclic number.
It is not a de Polignac number, because 5593970141 - 26 = 5593970077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5593970092 and 5593970101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5593970111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2796985070 + 2796985071.
It is an arithmetic number, because the mean of its divisors is an integer number (2796985071).
Almost surely, 25593970141 is an apocalyptic number.
It is an amenable number.
5593970141 is a deficient number, since it is larger than the sum of its proper divisors (1).
5593970141 is an equidigital number, since it uses as much as digits as its factorization.
5593970141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 170100, while the sum is 44.
The square root of 5593970141 is about 74792.8481941957. The cubic root of 5593970141 is about 1775.1704012564.
The spelling of 5593970141 in words is "five billion, five hundred ninety-three million, nine hundred seventy thousand, one hundred forty-one".
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