Base | Representation |
---|---|
bin | 11001011101010110000001… |
… | …01000001001111100010001 |
3 | 21100020000001202022112020002 |
4 | 30232223000220021330101 |
5 | 24314214343341104032 |
6 | 315022341410455345 |
7 | 14535461430021233 |
oct | 1456530050117421 |
9 | 240200052275202 |
10 | 55983835488017 |
11 | 1692467a701428 |
12 | 6342061294555 |
13 | 2531339bb9488 |
14 | db78bc680253 |
15 | 671404957862 |
hex | 32eac0a09f11 |
55983835488017 has 2 divisors, whose sum is σ = 55983835488018. Its totient is φ = 55983835488016.
The previous prime is 55983835487963. The next prime is 55983835488047. The reversal of 55983835488017 is 71088453838955.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53443688049361 + 2540147438656 = 7310519^2 + 1593784^2 .
It is a cyclic number.
It is not a de Polignac number, because 55983835488017 - 28 = 55983835487761 is a prime.
It is not a weakly prime, because it can be changed into another prime (55983835488047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27991917744008 + 27991917744009.
It is an arithmetic number, because the mean of its divisors is an integer number (27991917744009).
Almost surely, 255983835488017 is an apocalyptic number.
It is an amenable number.
55983835488017 is a deficient number, since it is larger than the sum of its proper divisors (1).
55983835488017 is an equidigital number, since it uses as much as digits as its factorization.
55983835488017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1161216000, while the sum is 74.
The spelling of 55983835488017 in words is "fifty-five trillion, nine hundred eighty-three billion, eight hundred thirty-five million, four hundred eighty-eight thousand, seventeen".
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