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560011117 is a prime number
BaseRepresentation
bin100001011000010…
…001011101101101
31110000202111211111
4201120101131231
52121330323432
6131322552021
716610005321
oct4130213555
91400674744
10560011117
11268125706
12137668611
138c037133
1454537981
153426e347
hex2161176d

560011117 has 2 divisors, whose sum is σ = 560011118. Its totient is φ = 560011116.

The previous prime is 560011097. The next prime is 560011121. The reversal of 560011117 is 711110065.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 528494121 + 31516996 = 22989^2 + 5614^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-560011117 is a prime.

It is a super-3 number, since 3×5600111173 (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (560011217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280005558 + 280005559.

It is an arithmetic number, because the mean of its divisors is an integer number (280005559).

Almost surely, 2560011117 is an apocalyptic number.

It is an amenable number.

560011117 is a deficient number, since it is larger than the sum of its proper divisors (1).

560011117 is an equidigital number, since it uses as much as digits as its factorization.

560011117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210, while the sum is 22.

The square root of 560011117 is about 23664.5540207290. The cubic root of 560011117 is about 824.2625142505.

The spelling of 560011117 in words is "five hundred sixty million, eleven thousand, one hundred seventeen".