Base | Representation |
---|---|
bin | 110100001010011101… |
… | …100100110100001111 |
3 | 12100120102212212212112 |
4 | 310022131210310033 |
5 | 1404202041144413 |
6 | 41421454454235 |
7 | 4021660665065 |
oct | 641235446417 |
9 | 170512785775 |
10 | 56010099983 |
11 | 21832272132 |
12 | aa3180437b |
13 | 5387c639c6 |
14 | 29d4a0c035 |
15 | 16cc3252a8 |
hex | d0a764d0f |
56010099983 has 2 divisors, whose sum is σ = 56010099984. Its totient is φ = 56010099982.
The previous prime is 56010099973. The next prime is 56010100007. The reversal of 56010099983 is 38999001065.
56010099983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56010099983 - 28 = 56010099727 is a prime.
It is a super-3 number, since 3×560100999833 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56010099973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28005049991 + 28005049992.
It is an arithmetic number, because the mean of its divisors is an integer number (28005049992).
Almost surely, 256010099983 is an apocalyptic number.
56010099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
56010099983 is an equidigital number, since it uses as much as digits as its factorization.
56010099983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 50.
The spelling of 56010099983 in words is "fifty-six billion, ten million, ninety-nine thousand, nine hundred eighty-three".
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