Base | Representation |
---|---|
bin | 110100001100011111… |
… | …100011100100101101 |
3 | 12100122211000000002211 |
4 | 310030133203210231 |
5 | 1404234302023423 |
6 | 41425113050421 |
7 | 4022553421111 |
oct | 641437434455 |
9 | 170584000084 |
10 | 56044173613 |
11 | 2184a52515a |
12 | aa410b6a11 |
13 | 5392033c0c |
14 | 29d935b741 |
15 | 16d030610d |
hex | d0c7e392d |
56044173613 has 2 divisors, whose sum is σ = 56044173614. Its totient is φ = 56044173612.
The previous prime is 56044173551. The next prime is 56044173617. The reversal of 56044173613 is 31637144065.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33890232649 + 22153940964 = 184093^2 + 148842^2 .
It is a cyclic number.
It is not a de Polignac number, because 56044173613 - 217 = 56044042541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56044173617) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28022086806 + 28022086807.
It is an arithmetic number, because the mean of its divisors is an integer number (28022086807).
Almost surely, 256044173613 is an apocalyptic number.
It is an amenable number.
56044173613 is a deficient number, since it is larger than the sum of its proper divisors (1).
56044173613 is an equidigital number, since it uses as much as digits as its factorization.
56044173613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 56044173613 in words is "fifty-six billion, forty-four million, one hundred seventy-three thousand, six hundred thirteen".
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