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56053981263437 is a prime number
BaseRepresentation
bin11001011111011000101011…
…01001000011011001001101
321100110201010022222010101022
430233230111221003121031
524321342023200412222
6315114502110123525
714543523624204143
oct1457542551033115
9240421108863338
1056053981263437
11169513a610a753
126353778ab05a5
132537b385b3b71
14dbb0547a1593
1567315cc61042
hex32fb15a4364d

56053981263437 has 2 divisors, whose sum is σ = 56053981263438. Its totient is φ = 56053981263436.

The previous prime is 56053981263431. The next prime is 56053981263457. The reversal of 56053981263437 is 73436218935065.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54673217609956 + 1380763653481 = 7394134^2 + 1175059^2 .

It is a cyclic number.

It is not a de Polignac number, because 56053981263437 - 214 = 56053981247053 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 56053981263437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56053981263431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28026990631718 + 28026990631719.

It is an arithmetic number, because the mean of its divisors is an integer number (28026990631719).

It is a 1-persistent number, because it is pandigital, but 2⋅56053981263437 = 112107962526874 is not.

Almost surely, 256053981263437 is an apocalyptic number.

It is an amenable number.

56053981263437 is a deficient number, since it is larger than the sum of its proper divisors (1).

56053981263437 is an equidigital number, since it uses as much as digits as its factorization.

56053981263437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97977600, while the sum is 62.

The spelling of 56053981263437 in words is "fifty-six trillion, fifty-three billion, nine hundred eighty-one million, two hundred sixty-three thousand, four hundred thirty-seven".