Base | Representation |
---|---|
bin | 110100001101101111… |
… | …100000101100100011 |
3 | 12100201021102212110021 |
4 | 310031233200230203 |
5 | 1404310133231342 |
6 | 41431142214311 |
7 | 4023226525156 |
oct | 641557405443 |
9 | 170637385407 |
10 | 56065133347 |
11 | 21860340553 |
12 | aa48124397 |
13 | 5396492122 |
14 | 29dc055c9d |
15 | 16d2096567 |
hex | d0dbe0b23 |
56065133347 has 2 divisors, whose sum is σ = 56065133348. Its totient is φ = 56065133346.
The previous prime is 56065133321. The next prime is 56065133437. The reversal of 56065133347 is 74333156065.
56065133347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (56065133437) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56065133347 - 219 = 56064609059 is a prime.
It is not a weakly prime, because it can be changed into another prime (56065133317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28032566673 + 28032566674.
It is an arithmetic number, because the mean of its divisors is an integer number (28032566674).
Almost surely, 256065133347 is an apocalyptic number.
56065133347 is a deficient number, since it is larger than the sum of its proper divisors (1).
56065133347 is an equidigital number, since it uses as much as digits as its factorization.
56065133347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 43.
The spelling of 56065133347 in words is "fifty-six billion, sixty-five million, one hundred thirty-three thousand, three hundred forty-seven".
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