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56065133317 is a prime number
BaseRepresentation
bin110100001101101111…
…100000101100000101
312100201021102212102011
4310031233200230011
51404310133231232
641431142214221
74023226525114
oct641557405405
9170637385364
1056065133317
1121860340526
12aa48124371
1353964920cb
1429dc055c7b
1516d2096547
hexd0dbe0b05

56065133317 has 2 divisors, whose sum is σ = 56065133318. Its totient is φ = 56065133316.

The previous prime is 56065133303. The next prime is 56065133321. The reversal of 56065133317 is 71333156065.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55128222436 + 936910881 = 234794^2 + 30609^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56065133317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 56065133317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56065133347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28032566658 + 28032566659.

It is an arithmetic number, because the mean of its divisors is an integer number (28032566659).

Almost surely, 256065133317 is an apocalyptic number.

It is an amenable number.

56065133317 is a deficient number, since it is larger than the sum of its proper divisors (1).

56065133317 is an equidigital number, since it uses as much as digits as its factorization.

56065133317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 40.

The spelling of 56065133317 in words is "fifty-six billion, sixty-five million, one hundred thirty-three thousand, three hundred seventeen".