Base | Representation |
---|---|
bin | 10000010100111111001… |
… | …10100011101011010111 |
3 | 1222122002200120022201122 |
4 | 20022133212203223113 |
5 | 33142433444332211 |
6 | 1105421451114155 |
7 | 55350453334106 |
oct | 10123746435327 |
9 | 1878080508648 |
10 | 561023433431 |
11 | 1a6a2411420a |
12 | 9089174295b |
13 | 40b9a92b276 |
14 | 1d2219a403d |
15 | e8d81456db |
hex | 829f9a3ad7 |
561023433431 has 2 divisors, whose sum is σ = 561023433432. Its totient is φ = 561023433430.
The previous prime is 561023433407. The next prime is 561023433437. The reversal of 561023433431 is 134334320165.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 561023433431 - 210 = 561023432407 is a prime.
It is a super-2 number, since 2×5610234334312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 561023433391 and 561023433400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (561023433437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280511716715 + 280511716716.
It is an arithmetic number, because the mean of its divisors is an integer number (280511716716).
Almost surely, 2561023433431 is an apocalyptic number.
561023433431 is a deficient number, since it is larger than the sum of its proper divisors (1).
561023433431 is an equidigital number, since it uses as much as digits as its factorization.
561023433431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 561023433431 its reverse (134334320165), we get a palindrome (695357753596).
The spelling of 561023433431 in words is "five hundred sixty-one billion, twenty-three million, four hundred thirty-three thousand, four hundred thirty-one".
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