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56111933058161 is a prime number
BaseRepresentation
bin11001100001000100100111…
…10101100110110001110001
321100200020201002111022200212
430300202103311212301301
524323314214330330121
6315201244410153505
714550645003265661
oct1460422365466161
9240606632438625
1056111933058161
1116973a34415882
126362a50a22895
1325404428b9466
14dbdb9120c1a1
1567490077d25b
hex330893d66c71

56111933058161 has 2 divisors, whose sum is σ = 56111933058162. Its totient is φ = 56111933058160.

The previous prime is 56111933058151. The next prime is 56111933058163. The reversal of 56111933058161 is 16185033911165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48224260808161 + 7887672250000 = 6944369^2 + 2808500^2 .

It is a cyclic number.

It is not a de Polignac number, because 56111933058161 - 214 = 56111933041777 is a prime.

It is a super-3 number, since 3×561119330581613 (a number of 42 digits) contains 333 as substring.

Together with 56111933058163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (56111933058163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28055966529080 + 28055966529081.

It is an arithmetic number, because the mean of its divisors is an integer number (28055966529081).

Almost surely, 256111933058161 is an apocalyptic number.

It is an amenable number.

56111933058161 is a deficient number, since it is larger than the sum of its proper divisors (1).

56111933058161 is an equidigital number, since it uses as much as digits as its factorization.

56111933058161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 583200, while the sum is 50.

The spelling of 56111933058161 in words is "fifty-six trillion, one hundred eleven billion, nine hundred thirty-three million, fifty-eight thousand, one hundred sixty-one".