Base | Representation |
---|---|
bin | 101000110100111100001… |
… | …0011000011101011110001 |
3 | 201212102121100110022212011 |
4 | 1101221320103003223301 |
5 | 1213413312330102241 |
6 | 15533434242002521 |
7 | 1116253616133145 |
oct | 121517023035361 |
9 | 21772540408764 |
10 | 5611245550321 |
11 | 18737969124a4 |
12 | 7675b6946441 |
13 | 3191a4791358 |
14 | 15582b379225 |
15 | 9ae64984281 |
hex | 51a784c3af1 |
5611245550321 has 2 divisors, whose sum is σ = 5611245550322. Its totient is φ = 5611245550320.
The previous prime is 5611245550319. The next prime is 5611245550331. The reversal of 5611245550321 is 1230555421165.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5061312069696 + 549933480625 = 2249736^2 + 741575^2 .
It is a cyclic number.
It is not a de Polignac number, because 5611245550321 - 21 = 5611245550319 is a prime.
Together with 5611245550319, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5611245550331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805622775160 + 2805622775161.
It is an arithmetic number, because the mean of its divisors is an integer number (2805622775161).
Almost surely, 25611245550321 is an apocalyptic number.
It is an amenable number.
5611245550321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5611245550321 is an equidigital number, since it uses as much as digits as its factorization.
5611245550321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180000, while the sum is 40.
The spelling of 5611245550321 in words is "five trillion, six hundred eleven billion, two hundred forty-five million, five hundred fifty thousand, three hundred twenty-one".
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