Base | Representation |
---|---|
bin | 1101011000001… |
… | …1111110111101 |
3 | 10220120221111021 |
4 | 3112003332331 |
5 | 103331141013 |
6 | 5322424141 |
7 | 1250653654 |
oct | 326037675 |
9 | 126527437 |
10 | 56115133 |
11 | 29748148 |
12 | 16962051 |
13 | b819929 |
14 | 764a19b |
15 | 4dd6a8d |
hex | 3583fbd |
56115133 has 4 divisors (see below), whose sum is σ = 57309120. Its totient is φ = 54921148.
The previous prime is 56115131. The next prime is 56115139. The reversal of 56115133 is 33151165.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 56115133 - 21 = 56115131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 56115098 and 56115107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56115131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596923 + ... + 597016.
It is an arithmetic number, because the mean of its divisors is an integer number (14327280).
Almost surely, 256115133 is an apocalyptic number.
It is an amenable number.
56115133 is a deficient number, since it is larger than the sum of its proper divisors (1193987).
56115133 is a wasteful number, since it uses less digits than its factorization.
56115133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1193986.
The product of its digits is 1350, while the sum is 25.
The square root of 56115133 is about 7491.0034708309. The cubic root of 56115133 is about 382.8482493439.
Adding to 56115133 its reverse (33151165), we get a palindrome (89266298).
The spelling of 56115133 in words is "fifty-six million, one hundred fifteen thousand, one hundred thirty-three".
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