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5613053711017 is a prime number
BaseRepresentation
bin101000110101110010000…
…0100101001001010101001
3201212121021100211102000211
41101223210010221022221
51213431013222223032
615534333513101121
71116346463216524
oct121534404511251
921777240742024
105613053711017
111874534540385
12767a203b77a1
1331940227aa1c
1415595d577bbb
159b01d5a0747
hex51ae41292a9

5613053711017 has 2 divisors, whose sum is σ = 5613053711018. Its totient is φ = 5613053711016.

The previous prime is 5613053710981. The next prime is 5613053711053. The reversal of 5613053711017 is 7101173503165.

It is a balanced prime because it is at equal distance from previous prime (5613053710981) and next prime (5613053711053).

It can be written as a sum of positive squares in only one way, i.e., 3646022215936 + 1967031495081 = 1909456^2 + 1402509^2 .

It is a cyclic number.

It is not a de Polignac number, because 5613053711017 - 231 = 5610906227369 is a prime.

It is not a weakly prime, because it can be changed into another prime (5613053711077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806526855508 + 2806526855509.

It is an arithmetic number, because the mean of its divisors is an integer number (2806526855509).

Almost surely, 25613053711017 is an apocalyptic number.

It is an amenable number.

5613053711017 is a deficient number, since it is larger than the sum of its proper divisors (1).

5613053711017 is an equidigital number, since it uses as much as digits as its factorization.

5613053711017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 66150, while the sum is 40.

The spelling of 5613053711017 in words is "five trillion, six hundred thirteen billion, fifty-three million, seven hundred eleven thousand, seventeen".