Base | Representation |
---|---|
bin | 101000110101110010000… |
… | …0100101001001010101001 |
3 | 201212121021100211102000211 |
4 | 1101223210010221022221 |
5 | 1213431013222223032 |
6 | 15534333513101121 |
7 | 1116346463216524 |
oct | 121534404511251 |
9 | 21777240742024 |
10 | 5613053711017 |
11 | 1874534540385 |
12 | 767a203b77a1 |
13 | 31940227aa1c |
14 | 15595d577bbb |
15 | 9b01d5a0747 |
hex | 51ae41292a9 |
5613053711017 has 2 divisors, whose sum is σ = 5613053711018. Its totient is φ = 5613053711016.
The previous prime is 5613053710981. The next prime is 5613053711053. The reversal of 5613053711017 is 7101173503165.
It is a balanced prime because it is at equal distance from previous prime (5613053710981) and next prime (5613053711053).
It can be written as a sum of positive squares in only one way, i.e., 3646022215936 + 1967031495081 = 1909456^2 + 1402509^2 .
It is a cyclic number.
It is not a de Polignac number, because 5613053711017 - 231 = 5610906227369 is a prime.
It is not a weakly prime, because it can be changed into another prime (5613053711077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806526855508 + 2806526855509.
It is an arithmetic number, because the mean of its divisors is an integer number (2806526855509).
Almost surely, 25613053711017 is an apocalyptic number.
It is an amenable number.
5613053711017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5613053711017 is an equidigital number, since it uses as much as digits as its factorization.
5613053711017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 66150, while the sum is 40.
The spelling of 5613053711017 in words is "five trillion, six hundred thirteen billion, fifty-three million, seven hundred eleven thousand, seventeen".
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