Base | Representation |
---|---|
bin | 1010011101001010… |
… | …11101100001110001 |
3 | 112111012121210110112 |
4 | 11032211131201301 |
5 | 42444013113132 |
6 | 2325002511105 |
7 | 256051126016 |
oct | 51645354161 |
9 | 15435553415 |
10 | 5613410417 |
11 | 242069536a |
12 | 1107b05495 |
13 | 6b5c71434 |
14 | 3b373970d |
15 | 22cc22ab2 |
hex | 14e95d871 |
5613410417 has 2 divisors, whose sum is σ = 5613410418. Its totient is φ = 5613410416.
The previous prime is 5613410357. The next prime is 5613410423. The reversal of 5613410417 is 7140143165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5482513936 + 130896481 = 74044^2 + 11441^2 .
It is a cyclic number.
It is not a de Polignac number, because 5613410417 - 220 = 5612361841 is a prime.
It is a super-2 number, since 2×56134104172 = 63020753019368227778, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5613410477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806705208 + 2806705209.
It is an arithmetic number, because the mean of its divisors is an integer number (2806705209).
Almost surely, 25613410417 is an apocalyptic number.
It is an amenable number.
5613410417 is a deficient number, since it is larger than the sum of its proper divisors (1).
5613410417 is an equidigital number, since it uses as much as digits as its factorization.
5613410417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 32.
The square root of 5613410417 is about 74922.6962742265. The cubic root of 5613410417 is about 1777.2243928639.
The spelling of 5613410417 in words is "five billion, six hundred thirteen million, four hundred ten thousand, four hundred seventeen".
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