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561482313313 is a prime number
BaseRepresentation
bin10000010101110101111…
…01000010111001100001
31222200021200000211120211
420022322331002321201
533144403433011223
61105535202334121
755365024626245
oct10127275027141
91880250024524
10561482313313
111a713a145489
129099b35a341
1340c41a16a1c
141d2668d4425
15e913589d0d
hex82baf42e61

561482313313 has 2 divisors, whose sum is σ = 561482313314. Its totient is φ = 561482313312.

The previous prime is 561482313311. The next prime is 561482313463. The reversal of 561482313313 is 313313284165.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 384688974289 + 176793339024 = 620233^2 + 420468^2 .

It is a cyclic number.

It is not a de Polignac number, because 561482313313 - 21 = 561482313311 is a prime.

Together with 561482313311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (561482313311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280741156656 + 280741156657.

It is an arithmetic number, because the mean of its divisors is an integer number (280741156657).

Almost surely, 2561482313313 is an apocalyptic number.

It is an amenable number.

561482313313 is a deficient number, since it is larger than the sum of its proper divisors (1).

561482313313 is an equidigital number, since it uses as much as digits as its factorization.

561482313313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 40.

Adding to 561482313313 its reverse (313313284165), we get a palindrome (874795597478).

The spelling of 561482313313 in words is "five hundred sixty-one billion, four hundred eighty-two million, three hundred thirteen thousand, three hundred thirteen".