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56153141625247 is a prime number
BaseRepresentation
bin11001100010010001011000…
…00011110100000110011111
321100211012001222200102120021
430301020230003310012133
524330003113224001442
6315232221440533011
714553634124315662
oct1461105403640637
9240735058612507
1056153141625247
111698a4605a1197
12636aa31621167
1325442ac172774
14dc1b800d96d9
15675a133e3e67
hex33122c0f419f

56153141625247 has 2 divisors, whose sum is σ = 56153141625248. Its totient is φ = 56153141625246.

The previous prime is 56153141625187. The next prime is 56153141625257. The reversal of 56153141625247 is 74252614135165.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56153141625247 is a prime.

It is a super-2 number, since 2×561531416252472 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 56153141625194 and 56153141625203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56153141625257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28076570812623 + 28076570812624.

It is an arithmetic number, because the mean of its divisors is an integer number (28076570812624).

Almost surely, 256153141625247 is an apocalyptic number.

56153141625247 is a deficient number, since it is larger than the sum of its proper divisors (1).

56153141625247 is an equidigital number, since it uses as much as digits as its factorization.

56153141625247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048000, while the sum is 52.

The spelling of 56153141625247 in words is "fifty-six trillion, one hundred fifty-three billion, one hundred forty-one million, six hundred twenty-five thousand, two hundred forty-seven".