Base | Representation |
---|---|
bin | 101000110111011101110… |
… | …1100101011001100100011 |
3 | 201212221121110222022010212 |
4 | 1101232323230223030203 |
5 | 1214010420323302111 |
6 | 15540132502444335 |
7 | 1116535231244315 |
oct | 121567354531443 |
9 | 21787543868125 |
10 | 5616671306531 |
11 | 187602058743a |
12 | 76866ba336ab |
13 | 31985a8ab99c |
14 | 155bc3bc77b5 |
15 | 9b180e8a98b |
hex | 51bbbb2b323 |
5616671306531 has 2 divisors, whose sum is σ = 5616671306532. Its totient is φ = 5616671306530.
The previous prime is 5616671306503. The next prime is 5616671306581. The reversal of 5616671306531 is 1356031766165.
It is an a-pointer prime, because the next prime (5616671306581) can be obtained adding 5616671306531 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5616671306531 - 226 = 5616604197667 is a prime.
It is a super-2 number, since 2×56166713065312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5616671306531.
It is not a weakly prime, because it can be changed into another prime (5616671306581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2808335653265 + 2808335653266.
It is an arithmetic number, because the mean of its divisors is an integer number (2808335653266).
Almost surely, 25616671306531 is an apocalyptic number.
5616671306531 is a deficient number, since it is larger than the sum of its proper divisors (1).
5616671306531 is an equidigital number, since it uses as much as digits as its factorization.
5616671306531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2041200, while the sum is 50.
The spelling of 5616671306531 in words is "five trillion, six hundred sixteen billion, six hundred seventy-one million, three hundred six thousand, five hundred thirty-one".
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