Base | Representation |
---|---|
bin | 101000111011111101100… |
… | …1110011111110110110111 |
3 | 201220212112102000000111221 |
4 | 1101313323032133312313 |
5 | 1214140204212302213 |
6 | 15544410551211211 |
7 | 1120326426014506 |
oct | 121677316376667 |
9 | 21825472000457 |
10 | 5626327072183 |
11 | 187a125a55054 |
12 | 76a505676b07 |
13 | 31a73918139c |
14 | 15645c34083d |
15 | 9b5489ed38d |
hex | 51dfb39fdb7 |
5626327072183 has 2 divisors, whose sum is σ = 5626327072184. Its totient is φ = 5626327072182.
The previous prime is 5626327072129. The next prime is 5626327072273. The reversal of 5626327072183 is 3812707236265.
5626327072183 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5626327072183 - 213 = 5626327063991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5626327072183.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5626327042183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2813163536091 + 2813163536092.
It is an arithmetic number, because the mean of its divisors is an integer number (2813163536092).
Almost surely, 25626327072183 is an apocalyptic number.
5626327072183 is a deficient number, since it is larger than the sum of its proper divisors (1).
5626327072183 is an equidigital number, since it uses as much as digits as its factorization.
5626327072183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 52.
The spelling of 5626327072183 in words is "five trillion, six hundred twenty-six billion, three hundred twenty-seven million, seventy-two thousand, one hundred eighty-three".
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