Base | Representation |
---|---|
bin | 110100011011100000… |
… | …110010010101100111 |
3 | 12101022101010221212012 |
4 | 310123200302111213 |
5 | 1410243303420341 |
6 | 41510113544435 |
7 | 4032033263144 |
oct | 643340622547 |
9 | 171271127765 |
10 | 56296154471 |
11 | 219697910a7 |
12 | aab157511b |
13 | 54022bb10b |
14 | 2a209d13cb |
15 | 16e74cc0eb |
hex | d1b832567 |
56296154471 has 2 divisors, whose sum is σ = 56296154472. Its totient is φ = 56296154470.
The previous prime is 56296154389. The next prime is 56296154479. The reversal of 56296154471 is 17445169265.
56296154471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56296154471 - 230 = 55222412647 is a prime.
It is a super-3 number, since 3×562961544713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56296154479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28148077235 + 28148077236.
It is an arithmetic number, because the mean of its divisors is an integer number (28148077236).
Almost surely, 256296154471 is an apocalyptic number.
56296154471 is a deficient number, since it is larger than the sum of its proper divisors (1).
56296154471 is an equidigital number, since it uses as much as digits as its factorization.
56296154471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1814400, while the sum is 50.
The spelling of 56296154471 in words is "fifty-six billion, two hundred ninety-six million, one hundred fifty-four thousand, four hundred seventy-one".
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